Astructural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of 98.9 mpa root m (90 ksi root in.) and a yield strength of 860 mpa (125,000 psi). the flaw size resolution limit of the flaw detection apparatus is 3.0 mm (0.12 if the design stress is one-half of the yield strength and the value of y is 1.0, determine whether or not a critical flaw for this plate is subject to detection.

a > 3 mm

so that critical flow is subject to detection  

Explanation:

plane strain fracture toughness = 98.9 MPa root m

yield strength = 860 MPa

flaw detection apparatus = 3.0 mm

Y = 1

solution

we know  critical stress formula that is

critical stress    .............................1

here K is design stress plane strain fracture toughness and a is length of surface creak

so here length of surface creak will be

length of surface creak a =  

put here value

a =  

a = 0.0168 m = 16.8 mm = 0.66 in

so

a > 3 mm

so that critical flow is subject to detection  

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