Ascientist needs 120 milliliters of a 20% acid solution for an experiment. the lab has available a 25% and a 10% solution. how many liters of the 25% and how many liters of the 10% solutions should the scientist mix to make the 20% solution?

the required quantity of solution of 10%  is 40 ml

the required quantity of solution of 25%  = 80 ml

Explanation:

let the required quantity of solution of 10% be x

and quantity of solution of 25% be (120 - x) ml

Hence, quantity of acid in x ml of 10 percentage solution isand similarly for 25% solution be

therefore total amount of acid is

we  need total solution of 120 ml of 20% so we have

after solving we get

solving for x we get

x = 40

therefore ,

the required quantity of solution of 10%  is 40 ml

the required quantity of solution of 25%  = 80 ml

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