from the enthalpies of reaction 2c(s)+o2(g) 2c(s)+o2(g)+4h2(g)→→2co(g)2ch3oh(g) δhδh=−221.0kj=−402.4kj 2 c (s)+ o 2 (g) → 2 c o (g) δh =−221.0 k j 2 c (s)+ o 2 (g)+4 h 2 (g) → 2 c h 3 o h (g) δh =−402.4 k j calculate δh δ h for the reaction co(g)+2h2(g) → ch3oh(g)