24x2+25x−47=−8x−3−53 is true for all values of x≠ 2 ax−2 ax−2 a
where a is a constant.
the 53 and entire first equation is divided by ax-2 and 2 is divided by a
What is the value of a?

A) -16
B) -3
C) 3
D) 16

multiply both sides of the given equation by ax−2. When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

i dont the the options but i believe its (oversee business) sorry if im wrong tho