Antique Accents tracks their daily profits and has found that the distribution of profits is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions. For full marks your answer should be accurate to at least three decimal places.

Answer;

a) 0.434

b) 0.983

c) 0.367

Explanation:

The exact question with the given parameters wasn't obtained online, but the same question, albeit with different parameters is then obtained. Hopefully, this Helps to solve the complete question with the required parameters.

Antique Accents tracks their daily profits and has found that the distribution of profis is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions For full marks your answer should be accurate to at least three decimal places. Compute the probability that tomorrow's profit will be

a) less than $16,791 or greater than $18,231

b) greater than $15,783

c) between $17,997 and $20,130

Solution

This is a normal distribution problem with

Mean = μ = $17,700

Standard deviation = σ = $900

a) less than $16,791 or greater than $18,231. P(x < 16,791) or P(X > 18,231) = P(X < 16,791) + P(x > 18,231)

We first standardize 16,791 and 18,231

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 16791

z = (x - μ)/σ = (16791 - 17700)/900 = - 1.01

For 18231

z = (x - μ)/σ = (18231 - 17700)/900 = 0.59

To determine the required probability

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

We'll use data from the normal probability table for these probabilities

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

P(z < -1.01) = 0.15625

P(z > 0.59) = 1 - (z ≤ 0.59) = 1 - 0.7224 = 0.2776

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59) = 0.15625 + 0.2776 = 0.43385 = 0.434 to 3 d.p

b) greater than $15,783. P(x > 15783)

We standardize 15783

z = (x - μ)/σ = (15783 - 17700)/900 = -2.13

To determine the required probability

P(x > 15783) = P(z > -2.13)

We'll use data from the normal probability table for this probability

P(x > 15783) = P(z > -2.13) = 1 - P(z ≤ - 2.13)

= 1 - 0.01659 = 0.98341 = 0.983 to 3 d.p.

c) between $17,997 and $20,130.

P(17,997 < x < 20,130)

We first standardize 17,997 and 20,130

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 17,997

z = (x - μ)/σ = (17,997 - 17700)/900 = 0.33

For 20,130

z = (x - μ)/σ = (20,130 - 17700)/900 = 2.70

To determine the required probability

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

We'll use data from the normal probability table for these probabilities

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

= P(z < 2.70) - P(z < 0.33)

= 0.99653 - 0.62930

= 0.36723 = 0.367 to 3 d.p.

Hope this Helps!!!

answer: compare a myth legend, or classic work of literature of you choice to a modern work that reinterprets it.focus on the similarities in theme between the newer work and the original, and provide examples that illustrate these themes from both works. the modern work may be any novel, movie, play, short story, or other storytelling medium with which you’re familiars long as it is clearly inspired by a myth, legend, or classic work of literature.

short-response prompt  

read the following excerpt from “fish cheeks” by amy tannin which tan recounts a christmas eve dinner.  

i fell in love with the minister’s son the winter i turned fourteen. he was not chinese, but as white as mary in the manger. for christmas i prayed for this blond-haired boy, robert, and a slim new american nose.  

on christmas eve i saw that my mother had outdone herself in creating a strange menu. she was pulling black veins out of the backs of fleshy prawns. the kitchen was littered with appalling mounds of raw food: a slimy rock cod with bulging fish eyes that pleaded not to be thrown into a pan of hot oil. tofu, which looked like stacked wedges of rubbery white sponges. a howl soaking dried fungus back to life. a plate of squid, their backs crisscrossed with knife markings so they resembled bicycle tires.  

after everyone had gone, my mother said to me. “you want to be the same as american girls on the outside.” she handed me an early gift. it was a miniskirt in beige tweed. “but in side you must always be chinese. you must be proud you are different. your only shame is to have shame.”