The options for 1st question:

a. 6x + 2y = 15

b. 3x - y = 7

c. 2x - 3y = 6

d. x + 3y = 1

show me the way of solving these 2 questions. you so much!

**brainliest to best answer**

The slope of the new line must be - 3

Subtract 6x from both sides

2y + 6x - 6x = 15 - 6x            

Collect like terms on the left

2y = 15 - 6x

Divide by 2

2y/2 = 15/2 - 6x/2

y = 7.5 - 3x

No matter how you represent it, the answer is the first equation on top. It's slope is -3

Problem Two

sqrt(x - 2) = x - 4              Square both sides

x - 2 = x^2 - 8x + 16         Switch sides

x^2 - 8x + 16 = x - 2          Subtract x from both sides.

x^2 - 8x - x + 16 = x - x - 2 Collect like terms on both sides.

x^2 - 9x + 16 = - 2             Add 2 to both sides

x^2 -  9x + 16 +2 = -2 + 2 Collect like terms

x^2 -  9x + 18 =  0             Factor    

(x - 3)(x - 6) = 0

x- 3 = 0

x  = 3

x - 6 = 0

x = 6

You have to be very careful with a question like this. Both answers have to checked: one of them may not work.

Let x = 3

sqrt(3 - 2) = 3- 4

sqrt (1) = - 1 This only works if you take the square root as +/- 1.

The minus root will wook

Let x = 6

sqrt(6 - 2) = x - 4

sqrt(4) = 6 - 4

2 = 2

x = 3 is kind of iffy.

x = 6 works.

I think I'd try 6 first. If the computer marks you wrong, you can include 3, but  I don't think it is quite correct.

this is under sat questions? my answer is by walking