Hurry

1.which are examples of perfectly inelastic collisions? check all that apply.
-a baseball bouncing off a bat
-bumper cars bumping off of each other
-a cue ball hitting an eight ball and stopping
-a plane landing on an aircraft carrier
-rain sticking to a window
-two train cars coupling together

7.two blocks are initially at rest with a compressed spring between them. when the spring is released, the 2m block moves to the left and the m block moves to the right. this represents an inelastic collision in a closed system.

what best describes the blocks after the spring is released?
-the total energy is zero.
-the total momentum is zero.
-the momentum of the m block is zero.
-the momentum of the 2m block is zero

8.momentum data about the same objects in the same closed system is shown below.

what value should be in place of the x?

3.4
3.5
3.6
3.7

1.

A plane landing on an aircraft carrier.

Rain sticking to a window.

Two train cars coupling together.

Explanation:

In perfectly inelastic collision when two objects collide each other then after collision they stick with each other as in this type of collision there is no separation after collision.

so here we have to choose such cases in the given all options

A plane landing on an aircraft carrier:

After landing the aircraft is in always contact with the ground so it is satisfying the condition of inelastic collision.

Rain sticking to a window:

Rain drops sticking to the window after it collide with it so it is the condition of perfect inelastic collision.

Two train cars coupling together:

Two cars collide and stick with each other so this is the condition of perfect inelastic collision.

2.

The total momentum is zero.

Explanation:

As we know that it is a type of perfect inelastic collision so here we can use momentum conservation as there is no external force on it.

Since we know that if net external force on a system is zero then momentum of the system is always conserved.

So in this case both the masses are at rest initially so initial momentum is zero here so at all instants of time final momentum is also zero.

so total momentum is zero

3.

Option C   3.6 (kg*m/s)

Explanation:

Since here in all cases we can see that it is following the condition of momentum conservation

Here by momentum conservation we can say that

initial momentum = final momentum

so from given table we know that

final momentum = 3.6 kg m/s

so initial momentum must be same

so value of x = 3.6 kg m/s

spare some change and give it to the poor

explanation:

plz : ((

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm