Acurrent of 9 a flows through an electric device with a resistance of 43 ω. what must be the applied voltage in this particular circuit? a. 4.8 v b. 4.8 a c. 387 v d. 387 a

387 volts

Explanation:
Ohm's law is used to relate voltage, current and resistance.
The formula is as follows:V = I * R
where:
V is the applied voltage (measured in volts)
I is the current flowing (measured in amperes)
R is the resistance (measured in ohm)

In the given, we have:
current (I) = 9 amperes
resistance (R) = 43 ohm

Substitute with the givens in the above formula to get the voltage as follows:
V = 9 * 43
V = 387 volts

Hope this helps :)

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