A7.5 cm object is 14 cm from a concave lens, which has a focal length of –7 cm. its image is 5 cm in front of the lens. what is the height of the image? round your answer to the nearest whole number. a. –3 cm b. 3 cm c. 21 cm

Given conditions:
height of object = 7.5cmdistance of object from mirror  = 14 cmfocus length = -7 cmimage distance =  ?
Using mirror formula: 
1/(focus length) = 1/(object distance) + 1/(image distance)
or, -1/7 = 1/14 + 1/(image distance)
or, image distance = -4.66cm (the image formed is a virtual image)

Also, magnification of image is:
image height /height of object = - image distance /object distance
or, image height = - image distance / object distance * height of object
or, image height = -(-4.66) / 14 * 7.5 = 2.49 = 3(nearest whole number)

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