Physics, 26.07.2019 18:00 margaret8800

Abaseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?

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Answer from: luke3416

The player will slide a distance of 2.04 m before coming to rest.

Given data:

The initial speed of player is, u = 4.0 m/s.

The coefficient of kinetic friction is, $\mu = 0.40$ .

Apply the work-energy principle as,

Work done by frictional force = Kinetic energy change

$W = \dfrac{1}{2}mv^{2} - \dfrac{1}{2}mu^{2}\\-f \times d = \dfrac{1}{2}mv^{2} - \dfrac{1}{2}mu^{2}\\-\mu mg \times d = \dfrac{1}{2}m(0^{2} )- \dfrac{1}{2}mu^{2}\\-\mu g \times d = - \dfrac{1}{2}u^{2}\\-(0.40) \times 9.8 \times d = - \dfrac{1}{2} \times 4^{2}\\d = 2.04 \;\rm m$

Thus, the distance slide by the player before coming to rest is 2.04 m.

Learn more about the work-energy principle here:

link

Answer from: Adithya27

The work done by the friction force to stop the player is equal to his loss of kinetic energy:
$W= \Delta K$

The work done by the friction force is the magnitude of the force $\mu m g$ times the distance covered by the player, d:
$W= \mu mg d$

The loss in kinetic energy is simply equal to the initial kinetic energy of the player, since the final kinetic energy is zero (the player comes to rest):
$\Delta K=K_i = \frac{1}{2}mv^2$

Substituting into the first equation, we get:
$\mu m g d= \frac{1}{2}mv^2$
from which we find d, the distance covered by the player:
$d= \frac{v^2}{2 \mu g}= \frac{(4.0 m/s)^2}{2 \cdot 0.4 \cdot 9.81 m/s^2}=2.04 m$

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

Answer from: Quest

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

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Abaseball player slides into third base with an initial speed of 4.0 m/s . if the coefficient of kin...