Physics, 27.07.2019 08:00 nerdykitty4586

This is a line graph used to describe the motion of an object. a graphic representation of velocity. also used to represent speed.

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Answer from: nick974

The velocity-time graph is used to represent the displacement of an object over a given period of time

Generally, a straight line graph shows uniform motion of an object over a given a period of time.

The velocity-time graph is used to represent the displacement of an object over a given period of time. When direction of an object is not important, the same graph can be used to explain the speed of an object.

The area of the curve under velocity-time graph is known as displacement.

Thus, we can conclude that, velocity-time graph is used to represent the displacement of an object over a given period of time.

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Answer from: ValeriaVironche953

Based on all the information that can be discerned from the
graph provided with the question, it may, for all we know, depict
the gyrations of the New York Stock Exchange during World War II,
or possibility the thickness of the ozone layer in the Earth's atmosphere
over the past 77 years.

It is almost certainly NOT a graphic representation of velocity, since it is
really tough to graph both speed and direction of a moving object.

Answer from: Quest

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm. the wire diameter is d = 0.9 mm. the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2) in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

Answer from: Quest

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: $k= \frac{1}{2}mv^2$ where m is the mass of the arrow and v its velocity. all the other options, instead, do not increase the kinetic energy of the system: - pulling farther back on the string : this will just increase the elastic potential energy of the system- holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)- decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)

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This is a line graph used to describe the motion of an object. a graphic representation of velocity....

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