When the potential difference between the plates of an ideal air‐filled parallel plate capacitor is 35 v, the electric field between the plates has a strength of 750 v/m. if the plate area is 4.0 × 10-2 m2, what is the capacitance of this capacitor?

The difference of voltage between the two plates of the capacitor is equal to the electric field intensity E times the distance between the plates:

so, from this we find d, the distance between the two plates of the capacitor:


And since we know also the area of the plates, we can find the capacitance:

Iwould sure like to answer your question but i honestly just don’t know