Physics, 27.07.2019 15:30 fatherbamboo

Which is a more objective measurement, sound intensity or loudness, and why? 1. sound intensity is exactly same as loudness. 2. sound intensity is a more objective and physical attribute of a sound wave because loudness can vary from person to person. 3. loudness is a more objective and physical attribute of a sound wave because sound intensity can vary from person to person. 4. sound intensity and loudness are subjective quantities; both can vary from person to person. 009?

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The correct answer is:
2. sound intensity is a more objective and physical attribute of a sound wave because loudness can vary from person to person

indeed, sound intensity is a measurable quantity, and so it is objective, while loudness is the subjective perception of the sound level, so it varies from person to person.

Answer from: hdjehd

2. sound intensity is a more objective and physical attribute of a sound wave because loudness can vary from person to person.

Explanation:

This is the statement that best describes the difference between sound intensity and loudness. Loudness refers to a subjective perception of how loud or soft a sound seems to a particular listener. However, this loudness is in fact determined by the amount of energy in sound waves. This is known as sound intensity and is measured in decibels. Sound intensity is an objective measurement that can better help us determine how loud a sound is.

Answer from: Quest

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

Answer from: Quest

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge, $v = \dfrac{e_p}{q}$ then the following gives us the potential difference, $\delta v = v_b - v_a$ $\begin{aligned} \delta v & = \dfrac{e_p_b}{q} - \dfrac{e_p_a}{q} \\ & = \dfrac{\delta e_p}{q} \end{aligned}$ the formula $\delta v = \delta e_p / q$ may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get $\delta e_p = q\delta v$ using q = 8.00 × 10⁻¹⁹ c and δv = 2.00 v, we get $\begin{aligned} \delta e_p & = (8.00\times10^{-19} \text{ c})(2.00\text{ v}) \\ & = 1.60\times 10^{-18}\text{ j} \end{aligned}$ the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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Which is a more objective measurement, sound intensity or loudness, and why? 1. sound intensity is...

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