How much work is required to lift a 2000-kg satellite from the surface of 7x10^6 the earth to an altitude of m?

The correct text of the problem is: "How much work is required to lift a 2000-kg satellite from the surface of the earth to an altitude of 7x10^6 m?"

Solution:The work needed to lift the satellite from the surface of Earth to an altitude h is equal to the increase in gravitational potential energy of the satellite moving from the surface of Earth to altitude h. This variation of gravitational potential energy is given by:

where m is the mass of the satellite, g is the gravitational acceleration and dh is the variation of altitude. The work is equal to this variation of energy: 

The mass of the satellite is m=2000 kg while the variation of altitude is

so we can plug these data into the equation to calculate the variation of gravitational potential energy, which is equal to the work done on the satellite:

Alkaline earth metals are found in group 2 of the periodic table.