The magnetic flux that passes through one turn of a 18-turn coil of wire changes to 4.5 wb from 13.0 wb in a time of 0.072 s. the average induced current in the coil is 190 a. what is the resistance of the wire?

We could answer the question through the help of Faraday's Law of Induction: 

Volts induced = - N•dΦ/dt

where N is the number of turns, and

Φ is the magnitude of the magnetic field. 

V = IR, or R = V / I 

V = -18 * [13Wb – 4.5Wb] / 0.072s 

V = -2125 volts the sign just specifies direction 

R = -2125V / 190 A 

R = -11.1842105 Ω

he kicked it 10 feet straight up into the air? i think this works.