A76 kg pilot at an airshow performs a loop de loop with his plane. at the bottom of the 52-m radius loop, the plane is moving 48 m/s. determine the normal force acting upon the pilot.

The solution for this problem is:

At bottom, both centrifugal force and weight are performing in the same direction. 
So we can say that, force would be computed by f = mg + mv^2 /r

= (76 x 9.81) + (76 x 48 x 48 / 52) 
= 745.6 + 3367.4 
Normal force = 4113 N is the answer

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.