You are standing on a large sheet of frictionless ice and holding a large rock. in order to get off the ice, you throw the rock so it has velocity 12.0 m/s relative to the earth at an angle of 35.0∘ above the horizontal. your mass is 61.0 kg and the rock's mass is 4.00 kg . part a what is your speed after you throw the rock?

The answer is vc=-0.645m/s

Explanation:

Hello!

Let's solve this!

First we will write down the data:

mc (child's mass): 61kg

mr (rock mass): 4kg

vr (rock speed): 12m / s

angle: 35 °

We will calculate the velocity in x of the rock:

vxr = 12m / s * cos (35 °) = 9.83m / s

mc * vc + mr * vrx = 0

We cleared vc that is the incognita

vc = -mr * vrx / mc

vc = (4kg * 9.83m / s) / 61kg

vc = -0.645m / s

The speed of the person is 0.645 m / s. It is negative because the direction in which the person moves is contrary to the direction to which the rock throws.

The answer is vc=-0.645m/s

a and c

c is 100% but i am confused in a

massxgravity x heght=weightxheight= pe

4900=490xh

h=10