Explain what happens to the pitch of a cell phone ring when the wavelength of a sound wave increases.

The correct answer is: Pitch of a cell phone ring decreases when wavelength of sound wave increases.

Explanation:
According to wave-equation:
v=fλ
f = v/λ

Where f = frequency (pitch) of the wave.
λ = wavelength of the wave
v = speed of the wave

The frequency of the wave is INVERSELY proportional to the wavelength of the wave. It means that if the wavelength of a sound wave increases the pitch (frequency) of a cell phone ring decreases.

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