Physics, 29.07.2019 17:30 duplessistoccara

Ahockey puck is hit on a frozen lake and starts moving with a speed of 12.0 m/s. exactly 5.0 s later, its speed is 6.0 m/s. what is the puck's average acceleration? what is the coefficient of kinetic friction between the puck and the ice?

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Answer from: mrmendrala

a. The puck's average acceleration is equal to -1.2 m/s^2 .

b. The coefficient of kinetic friction between the puck and the ice is 0.122.

Given the following data:

Initial speed = 12.0 m/sTime = 5.0 seconds.Final speed = 6.0 m/s

a. To find the puck's average acceleration:

Mathematically, acceleration is given by the formula;

$Acceleration = \frac{V_f\; - \;V_i}{t}$

Where:

V is the final velocity. U is the initial velocity. t is the time measured in seconds.

$Acceleration = \frac{6\; - \;12}{5}\\\\Acceleration = \frac{-6}{5}$

Average acceleration = -1.2 m/s^2

b. To find the coefficient of kinetic friction between the puck and the ice:

The frictional force acting between the puck and the ice is given by the formula;

$F = uN = -umg\\\\F = -umg\\\\\frac{F}{m} = -ug$ ....equation 1.

But, $a = \frac{F}{m}$ ....equation 2.

We know that acceleration due to gravity (g) of an object is equal to 9.8 meter per seconds square.

$a = -ug\\\\u = \frac{-a}{g}\\\\u = \frac{-(-1.2)}{9.8} \\\\u = \frac{1.2}{9.8}$

Coefficient of kinetic friction, u = 0.122

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Ahockey puck is hit on a frozen lake and starts moving with a speed of 12.0 m/s. exactly 5.0 s later...

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