Amixing blade on a food processor extends out 3 inches from its center. if the blade is turning at 600 revolutions per minute, what is the linear velocity of the tip of the blade in feet per minute? (round your answer to the nearest whole number.)

The linear  velocity of the tip of the blade is 940.94 ft/min.

Explanation:

It is given that,

A mixing blade on a food processor extends out 3 inches from its center, r = 3 inches = 0.0762 meters

Angular speed of the blade,  

Let v is the linear velocity of the tip of the blade. The relation between the angular velocity and the linear velocity is given by :

v = 4.78 m/s

or

Since, 1 m/s = 196.85 ft/min

4.78 m/s = 940.94 ft/min

So, the linear  velocity of the tip of the blade is 940.94 ft/min. Hence, this is the required solution.          

this means that the temperature of both substances will be equal

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂