How much heat is absorbed by a 43g iron skillet when its temperature rises from 5oc to 25oc?

This problem is described by the formula q=mc*deltaT
q is heat, m is mass, c is specific heat capacity (which varies based on substance, I googled the value for iron, which gave me 0.444 J/g*°C) and deltaT is temperature change.
Temperature change can be solved for by subtracting the initial temperature from the final, Tf-Ti, so 25-5 = 20 °C, which gives us everything we need to solve for q.
q= 43 g * 0.444 J/g*°C * 20 °C
q= 381.84 J of heat absorbed

381.84 that how much heat absorbs

Depotion can i think