Compare the magnitude of the electromagnetic and gravitational force between two electrons separated by a distance of 2.00 m. assume the electrons have a mass of 9.11 × 10^–31 kg and a charge of 1.61 × 10^–19 c. round to two decimal places. fe = × 10^–29 n fg = × 10^–71 n fe/ fg= × 10^42 answer as soon as possible!

First you need to know about two laws, which are:
1) Coulomb's law
2) Newton's law of gravitation

1.
According to Coulomb's law, Electric force between TWO charges is:
-- (A)

Where, k = 1/(4*π*epsilon_not) =  

Both  and = -1.61 x  C
r = Distance between the two charges = 2.00m

Plug-in the above values in (A), you would get:

= (9 *  ) (1.61 *   * 1.61 * ) / (2*2)  

=  N

2.
According to Newton's law of gravitation:
-- (B)

Where G = Gravitational constant = 6.674 * 

m1 = m2 = Mass of the electron =  kg
r = 2.0 m

Plug-in the above values in (B), you would get:

= (6.674 * ) (   *  }[/tex]) / (2*2)  

=  N

= 

Now do Fe over Fg, you would get:


Ans: So the blanks are:
1) 5.82
2) 1.38
3) 4.23

-i

3x + 2x = both people using the same measure of like 5x = x= 25 meters per second. 25ms. it takes them 4 seconds to

The answer would be a) -80of