Suppose an electric field with a magnitude of 2.8 e 4 n/c at a certain location, points due south. if a charge of -4.0 e -6 c is brought to the location, what is the electrostatic force that acts on this charge?

0.112 N due north.

Explanation:

Data:

E = 2.8 * 10^4 N/c
q =  -4.0 * 10^ - 6C
F =?

Formula:

E = F / q

This formula tells that the magnitude of the electric field equals the electrostatic force divided by magnitude of the charge.

From that equation you get: F = Eq, which is what you need use for this problem.

Solution:

F= Eq = 2.8 * 10^4 N/C * (-4.0 * 10^ - 6 C) = - 0.112 N

The negative sign means that the force points in the opposite direction of the electric field, this is the force points toward the north.

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