An oil fired steam generator is connected to a steam engine which produces 50kw of power when using oil of energy content 47mj/kg at a rate of 19.9kg/h. steam temperature is500c and cooling water temperature is 15 c. calculate the: a. heat rejection rate. b. the ovrerall efficiency of the plant. c. maximum efficiency attainable by the engine.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

answer; how far out of place which the object finished relative to the starting location;