A2kg marble is moving at 3 m/s when it strikes another 4kg marble moving in the opposite direction at -3 m/s. what will be the velocity of the 4kg marble after the collision of the 2kg marble's new velocity is -4 m/s. also state the direction of the 2kg marble after they hit.

Momentum is conserved after the collision 

Momentum of 2 Kg before collision = 2 * 3 = 6
Momentum of 4 kg  before collision = 4 * -3 = -12

so 6 + -12 = 2 * -4 + 4 *x   where x is velocity of 4kg marble.

4x - 8 = -6
4x = 2
x = 0.5 

Velocity of 4 kg marble is 0.5 m/s after collision

The 2 kg marble will move in the opposite direction to which it was moving before the collision.

Answerboth technicians (a) and (b);

We can infer that star y is closer but other factors must be considered including the heat of the star, the mass, and the brightness of the star. even though star x seems dimmer it may just be less bright or contain less heat.