An ice cube (mass = 1.0 kg) slides down an inclined serving tray with an acceleration of 4.0 meters per second. ignoring friction how much force is pulling the ice cube down the serving tray?

Ten newton force is pulling the ice cube towards the tray

That would be the corect answer hope this

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.