Physics, 03.08.2019 03:00 Angela1998

What best describes an impulse acting on an object? a) the net force on an object divided by the time of impact b) the velocity of an object divided by its mass c) the product of an object's mass and the time of force impact d) the product of an object's mass and its change in velocity

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Answer from: zozo72

option (D)

Explanation:

If a large force acting on a body for a very small interval of time, it is called impulse.

Impulse is a vector quantity. its SI unit is kg m/s.

The formula of impulse is given by

Impulse = Force x Δ t = change in momentum.

Answer from: whimsy

D) the product of an object's mass and its change in velocity

Explanation:

The impulse is defined as:

$I = F . \Delta t$ (1)

Where I is the impulse, F is the force and t is the time whereby the force will be applied on the object.

By using Newton's second law, the impulse can be related with the mass and the change in velocity as a consequence of the acting force:

F = ma (2)

Where F is the force, m is the mass and a is the acceleration.

The acceleration can be determined using the equations for a Uniformly Accelerated Rectilinear Motion:

$a = \frac{\Delta v}{\Delta t}$ (3)

Where $\Delta v$ is the change in velocity ( $v_{2} - v_{1}$ ) and $\Delta t$ is the interval of time ( $t_{2} - t_{1}$ )

Remember that the acceleration is defined as the change in velocity in an interval of time.

By replacing equation (3) in equation (2) it is gotten:

$F = m\frac{\Delta v}{\Delta t}$

$F . \Delta t = m\Delta v$

$F . \Delta t = m(v_{2} - v_{1})$

But $F . \Delta t$ is the impulse according with equation (1), therefore:

$I = m(v_{2} - v_{1})$

So what best describes an impulse acting on an object is the product of an object's mass and its change in velocity.

Answer from: Quest

connect the batteries in series and hope

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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