Apendulum swings with amplitude 0.01 m and period of 3.0 s . part a what is its maximum speed?

The pendulum reaches the maximum speed at the lowest point of its movement and the elongation at this point is zero (x = 0). The equation of speed should be applied as a function of the elongation, which is shown below:

 V = ± w √ (A^2 - x^2)

 We know that the elongation is 0 (x = 0), so the previous equation is as follows:

 V = ± w x A

 w = 2π/ T

 V: speed.

 w: angular speed.

 A: amplitude.

 T: period.

 Let's proceed to calculate the angular speed:

 w = 2π/ 3.0 s

 w = 2.09 rad/s

 We already know the value of the angular speed and the amplitude, so we can calculate the maximum speed of the pendulum, which results in:

 V = 0.0209 m/s

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