Calculate the electric field strength if the potential across charged plates is 12 volts and their separation is 0.4 cm. 5v/m 0.05 v/m 30 v/m 3,000 v/m calculate the force a test charge of 0.001 coulomb would experience in the field across charged plates of 12 volts and separation of 0.4 cm. 5 times 10-^3 n 5 times 10-^5 n 5 times 10 -^2n 3

Answer :

(1) The electric field strength is, 3,000 V/m

(2) The force a test charge is, 3 N

Solution for part 1 :

Formula used for electric field strength :

where,

E = electric field strength

V = potential = 12 volts

d = distance between the charge = 0.4 cm = 0.004 m     (1 m = 100 cm)

Now put all the given values in the above formula, we get the electric field strength.

Therefore, the electric field strength is, 3000 V/m

Solution for part 2 :

Another formula used for electric field strength with force :

where,

E = electric field strength = 3000 V/m     (from the solution of part 1)

F = force

q = charge = 0.001 coulomb

Now put all the given values in the above formula, we get the force a test charge.

Therefore, the force a test charge is, 3 N

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