A4.2 kg sled is being pulled along a snow-covered road with a rope that exerts a horizontal force of 6.0 n and, at that moment, is accelerating at 1.1 m/s2 on level ground with friction having no significant effect. what is the normal force on the sled?

the body is moving horizontally, it doesnt matter watever kind of horizontal forces are acting.
 Therefore the normal force is equal to the weight
 N=mg=4.2*9.8=41N
 Note: the other data in the problem have no relevance
 answer
 the normal force on the sled is 41N 

Normal force is equal to the formula of mg where m is the gravitational acceleration and g is the mass of the object. This is only applicable when the force is acting in the direction of the gravitational field and the  object is placed horizontally.So the formula is normal force = mg since the problem depicts what the statement is talking about.
So NF = mg= 9.8 m/s^2* 4.2kg= 41.16 N or 41 N

Ireally just need to get finished with precal! i’m really sorry i have to do this! hope this !