How much heat is needed to vaporize 33.3 grams of ethyl alcohol at its boiling point of 78.0°c? the latent heat of vaporization of ethyl alcohol is 857 j/g. round your answer to three significant figures.

28,538 J

Explanation:

The heat needed to vaporize the ethyl alcohol is given by:

where

m = 33.3 g is the mass of the ethyl alcohol

is the latent heat of vaporization of alcohol

Since the alcohol is already at its boiling point (78 degrees), we don't need any other heat to bring it at this temperature. Therefore, we can simply calculate the heat needed by putting the numbers inside the formula:

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

this is a good question! i'll do some research and come back when i have the answer!