Asealed jar has 0.20 moles of gas at a pressure of 300.12 kpa and a temperature of 229 k. what is the volume of the jar?

From  ideal  gas  equation  v=nRT/P  where  n  is  number  of  moles,   ,R  is  the  gas  constant, T is the temperature  and  P  is  the  pressure
P=300.12kpa
n=0.2moles
R(the  gas  constant)=8.3145  L.kpa/mol.k
T=229k
v=?
0.2mol  x { ( 8.1345  l.kpa/mol.k   x229  k)/300.12   kpa}=1.27  L

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