When a 57-gram piece of aluminum at 100oc is placed in water, it loses 735 calories of heat while cooling to 30oc. calculate the specific health capacity of the aluminum

specific heat capacity of aluminium is 0.184 Calroie/ gram-K.

Explanation:

As we know that heat transferred to a given material to change its temperature is given as

here we know

Q = heat given = 735 calorie

m = mass = 57 gram

initial temperature = 100 degree C

final temperature = 30 degree C

now by above formula we will have

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j