Abike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. determine the acceleration of the bike

Explanation:GiVeNA bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. Determine the acceleration of the bikeT0 FInDAccelerationSoLuTi0NLet acceleration of the bike is a m/sec^2 bike started from rest so its initial speed will zero i.e.u=0

It reaches at a speed of 7.10 m/s i.e final

speed v= 7.10 m/s

In reaching speed 7.10 m/s ,it covered distance 35.4 m. Apply equation of motion which relates

u ,v,a and s

V^2=u^2+2 as

FiNaL AnsWeRSo acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.

This is what i found on google “what happens to the bond angle when you add or remove an electron domain? the bond angle decreases as you add domains 5. can you force the atoms into new configurations by pushing atoms around? note: we can think of a bond or a lone pair of electrons as a “domain” of electrons.” i hope this you

Ithink the answer would be 1,350!