A0.45-kilogram football traveling at a speed of 22 meters per second is caught by an 84-kilogram stationary receiver. if the football comes to rest in the receiver's arms, the magnitude of the impulse imparted to the receiver by the ball is

The magnitude of the impulse imparted to the receiver by the ball is  –9.9 Kg•m/s

From the question given above, the following data were obtained:

Mass of ball (m) = 0.45 Kg

Initial velocity (u) = 22 m/s

Final velocity (v) = 0 m/s

The magnitude of the impulse imparted to the receiver by the ball can be obtained as follow:

Impulse = Change in momentum

I = m(v – u)

I = 0.45 (0 – 22)

I = 0.45 (–22)

Thus, we can conclude that the magnitude of the impulse imparted to the receiver by the ball is  –9.9 Kg•m/s

Learn more: link

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west