In a shuffleboard game, the puck slides a total of 12 m on a horizontal surface before coming to rest. if the coefficient of kinetic friction between the puck and board is 0.10, what was the initial speed of the puck?

Given that,   

Puck slide total Deltax = 12m 

  Puck and board Mk = 0.10   

  Find the initial speed = ?   

 We know that,  

  Vf^2-Vi^2 = 2a Deltax 

  -Vi^2 = -2MkgDeltax (1)    

 then, 

  fk = -Mk mg = ma 

  a = -Mkg (2)   

 From equation (1), 

  Vi^2 = 2MkgDeltax 

  Vi = âš2MkgDeltax [g=9.8m/s^2] 

  Vi = âš2(0.10)(0.98)(12) 

  Vi = âš0.2(9.8)(12)

   Vi = âš1.92(12) 

  Vi = âš23.52 

  Vi = 4.8 m/s   

 Therefore the initial speed of the puck Vi = 4.8 m/s

Good moring let me you on this question the answer the electric force  have a good day ; )