Acyclist rides in a circle with speed 3.2 m/s. what is his centripetal acceleration if the circle has a radius of 12m ?

The equation for centripetal acceleration is Ac=v^2/r.

Ac= 3.2^2/12

Ac=10.24/12

Centripetal acceleration= .85

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

current flows in a wire