Consider a box sitting on the floor. if you applied 275 newtons of force horizontally to the right and the frictional force was 25 newtons, what would be the magnitude and direction of the net force?

Assume the frictional force is horizontal to the left.

To find the magnitude of the force, we will first subtract 25 from 275.

The magnitude is 250 newtons of force horizontally to the right.

A., d., and f i think

Average net force: ∑f = fapp + fgrav = 8.20 + (-9.81m/s²)(0.500 kg)           = 3.295 n          = 3.30 nvelocity of object∑f = maa = ∑f / m = 3.295 n / 0.500 kg = 6.59 m/s²v² = v₀² + 2adv = √(v₀² + 2ad)v = √[ 0² + 2(6.59m/s²)(1.50m) ]v = 4.45 m/s