Physics, 22.07.2019 15:20 zoeann480

1. complete the following. when light is incident parallel to the principal axis and then strikes a lens, the light will remain parallel after refracting through the lens the light will refract through the focal point on the opposite side of the lens the light will not refract at all 2.complete the following. when light is incident through the focal point, and then strikes a mirror, the light will reflect parallel to the principal axis the light will reflect back through the focal point the light will not reflect at all 3.use your work from ray tracing assignment 6.11 and the diagram below to answer the following question. an object is 2.0 cm from a double convex lens, with a focal length of 1.5cm. calculate the image distance. remember to include your data, equation, and work when solving this problem. 4. in your own words, describe the three steps in ray tracing used to identify where an image forms. 5. in your own words, explain how you can tell if an image is real or virtual.

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Answer from: leilei2003

The correct options are as follows:
1. The light will refract through the focal point on the opposite side of the lens.
The principal axis refers to the line that is passing through the center of the surface of a lens. The focal point of a lens is the point in space where parallel light rays meet after passing through the lens. Thus, when a light incident parallel to the principal axis strike a lens, the light will refract through the focal point of the lens.

2. The light will reflect parallel to the principal axis.
When light is incident through the focal point and allow to strike a mirror; the light will be reflected back parallel to the principal axis. Reflection here means that, the light will be thrown back by the mirror without absorbing it.

3. Object distance [D1] = 2 cm
Focal length [F] = 1.50 cm
Image distance [D2] = ?
The correct formula to use is:
I/F = 1/D1 + 1/D2
1/D2 = 1/F - 1/D1
1/D2 = 1/1.50 - 1/2.0 = 1/6
D2 = 6 cm
Therefore, image distance = 6 cm.

4. In physics, ray tracing are used to find the position and size of an image formed by lenses. The following steps should be followed in ray tracing:
a. The line parallel to the principal axis refract through the focus on the other side.
b. The line through the center of the lens go straight through to the other side.
c. The line from the focal point refract parallel to the principal axis.
5. An image can either be a virtual image or a real image. A virtual image has the following characteristics: The image is formed in a location where light rays do not actually reached. The image is usually located behind the mirror. The image is upright and the same size as the object.
For a real image, the image is formed in a location where light rays actually pass through. The image is located before the mirror.

Answer from: kaaylon8285

Responses;

1. The light will refract through the focal point on the opposite side of the lens.

2. The light will reflect parallel to the principal axis.

3. The image distance is 6 meters from the lens.

4. The three steps are;

Light parallel to the principal axis passes through the focus.Light from the focus emerges parallel to the principal axis.Light incident from the center of curvature travels straight through.

5. An image is real or virtual if the focus points are from converging or diverging rays respectively.

Reasons and Methods for arriving at the above Responses:1. Direction of light incident parallel to the principal axis

Light parallel to the principal axis passing through the lens refracts

through the focal point.

The correct option is; the light will refract through the focal point on the opposite side of the lens.2. Direction of the light incident from focus

The question is the inverse of the motion of light in question 1, with

respect to mirrors.

Therefore;

When light is incident through the focal point, and then strikes a mirror, the light will reflect parallel to the principal axis.3. Image distance from lens

Distance of the object from the convex lens, u = 2.0 cm

Focal length of the lens, f = 1.5 cm

Required:

The image distance from the lens

Solution:

$\displaystyle The \ convex \ lense \ formula \ is; \ \frac{1}{f} = \mathbf{\frac{1}{v} + \frac{1}{u}}$

Therefore;

$\displaystyle \frac{1}{1.5} = \mathbf{\frac{1}{v} + \frac{1}{2.0}}$

$\displaystyle \frac{1}{v} = \frac{1}{1.5} - \frac{1}{2} = \frac{1}{6}$

$\displaystyle \frac{1}{v} = \frac{1}{6}$

The image distance from the mirror, v = 6 cm4. Description of the steps in ray tracing

The three steps in ray tracing used to identify where an image forms based on the rules for the construction of ray diagrams are;

Step 1.The ray drawn from the object parallel to the principal axis passes through the focus after reflection or refraction.Step 2. A ray incident from the the focus on the lens (or mirror) is refracted (reflected) parallel to the principal axis.Step 3; A ray incident from the optical center of a lens (or mirror) is refracted straight through.5. Real and virtual image

An image is real if it is formed by combination of the focus points of converging light rays from the source.

An image is virtual if it is created by the combination of the points of focus that is made by the extension of diverging rays.

Learn more about reflection and refraction here:

link

Answer from: Quest

for this one it would be d bump/forearm pass

When receiving a serve,you ideally want the first pass to be ?

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

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