Asatellite revolves around a planet at an altitude equal to the radius of the planet. the force of gravitational interaction between the satellite and the planet is f0. then the satellite moves to a different orbit, so that its altitude is tripled. find the new force of gravitational interaction f2.

We can use the equation for the force of gravity to solve this question. F = G M1 M2 / R^2 Let R be the radius of the planet. f0 = G M1 M2 / (2R)^2 f0 = (1/4) x (G M1 M2 / R^2) We can find an expression for f2. f2 = G M1 M2 / (4R)^2 f2 = (1/16) x (G M1 M2 / R^2) We can express f2 in terms of f0: f2 = (4/16) x f0 f2 = 0.25 f0

Try b? sorry if i’m incorrect

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