Aday on a distant planet observed orbiting a nearby star is 21.5 hours. also, a year on the planet lasts 59.1 earth days.* calculate the average angular speed of the planet about its own axis of rotation in radians per second, with the second as measured on earth.

8.24x10^-5 rad/sec The key thing to remember for this problem is that in the process of orbiting its parent star, the planet will rotate one more time than the number of days the planet sees as it's year. For instance, on Earth, a day is 24 hours, or 1440 minutes long. But the sidereal day (how long the Earth takes to rotate about it's axis as referenced to distant stars) is about 4 minutes shorter. And if you take 1440 and divide by 365.2425, you'll get 3.9 minutes or "about 4 minutes". So let's calculate how many times the observed planet rotates. 59.1 days/year * 24 hours/day = 1418.4 hours/year Since the planet has a "day" of 21.5 hours, that means that the planet experiences 1418.4/21.5 = 65.97 days per year. Add the extra rotation needed and the planet turns on its axis 66.97 times per local year. Now, divide by the length of its year to get the number of rotations per earth day 66.97/59.1 = 1.133164129 rotations per 24 hours. Convert from rotations to radians. 1.133164129 * 2 * pi = 7.119880203 rad Now divide by the number of seconds in a day (24*60*60 = 86400) 7.119880203 rad / 86400 sec = 8.2406x10^-5 rad/sec Rounding to 3 significant figures gives 8.24x10^-5 rad/sec

The answer is a i think

That big glowy thing in the sky is called the sun