Afarm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the trailer ( ignore friction.)

The force exerted by gravity is:

F = m g

F = 3300 kg * 9.8 m/s^2

F = 32,430 N

The force exerted due to the inclined plane is:

F tractor = 32,430 N * sin 14

F tractor = 7,823.75 N      (answer)

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j