Consider a sign suspended on a boom that is supported by a cable, as shown. what is the proper equation to use for finding the net force in the y direction? fnety  = (ft)(sin 32°) +  fgfnety  = (ft)(sin 32°) –  fgfnety  = (ft)(cos 32°) +  fgfnety  = (ft)(cos 32°) –  fg

B: Fnety = (FT)(sin 32°) – Fg

Explanation:

33: i think it’s b

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day