Agood quarterback can throw a football at 27 m/s (about 60 mph ).  how long is the ball in the air?

Assume that
(a) Air resistance is negligible,
(b) g = 9.8 m/s², acceleration due to gravity,
(c) The launch angle is 45°, in order to attain maximum horizontal range.

The horizontal and vertical launch velocities are equal, and each is equal to
(27 m/s)*cos(45°) = 19.09 m/s.

The time to attain maximum height is one half of the time of flight.
Because the vertical velocity is zero at maximum height, half the time of flight, t₁, is given by
19.09 - 9.8t₁ = 0
t₁ = 1.948 s

The time of flight is
2t₁ = 3.896 s

The horizontal distance traveled is
3.896*19.09 = 74.375 m

The time of flight is 3.9 s (nearest tenth)

B) as the temperature increases, the kinetic energy of the particles increases.|-/

This did i unseated, sorry