Acalifornia condor is approaching its nest with a large chunk of carrion in its beak. as it approaches, it makes an upward swoop, achieving a momentary upward velocity of 12.8 m/s when the carrion falls from its mouth, hitting a cliff outcropping 32.1 m below. determine the speed of the carrion upon hitting the outcropping. (28.2 m/s)

Since the bird is initially going up, therefore upon falling form its mouth, the carrion was also going up at similar velocity of 12.8 m/s before it falls down. So calculate the distance taken during this time of momentarily going up:

(v = final velocity at the peak before it falls = 0, v0 = initial velocity = 12.8 m/s, g = gravity = 9.81 m/s^2, d is height taken)

v^2 = v0^2 - 2 g d

0 = 12.8^2 - 2 * 9.81 * d

d = 8.35 m

SO total distance it fell is:

d* = 8.35 m + 32.1 m = 40.45 m

So calculating for final velocity v (v0 = 0 since it stops at the peak before falling down):

v^2 = v0^2 + 2 g d

v^2 = 0 + 2 * 9.81 * (32.1 + 8.35)

v^2 = 793.642

v = 28.17 m/s = 28.2 m/s

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.