If you dropped a rock and it fell 4.9 m in 1 s , how far would it fall in 3 s

The formula relevant for this is:

h = v0t + 0.5 gt^2

since the rock was dropped, therefore:

h = 0.5 gt^2

we can see that:

h / t^2 = 0.5 g = constant

therefore:

4.9 m / (1 s)^2 = h / (3 s)^2

h = 44.1 m 

if they have a finite resultant

im sorry i dont know