You're driving down the highway late one night at 20m/s when a deer steps onto the road 60 m in front of you. your reaction time before stepping on the brakes is 0.50s, and the maximum deceleration of your car is 10m/s2.

Traveling speed = 20 m/s

Within the reaction time of 0.050 s, the distance traveled is
s₁ = (20 m/s)*(0.5 s) = 10 m

The time required to stop with a deceleration of 10 m/s² is
t = (20 m/s)/(10 m/s²) = 2 s.

The distance traveled before coming to a stop is
s₂ = (20 m/s)*(2 s) - 0.5*(10 m/s²)*(2 s)²
    = 20 m

Total distance traveled before coming to a stop is
s₁ + s₂ = 10 + 20 = 30 m

This distance of 30 m is less than 60 m. so the vehicle will not hit the deer.