What is the internal energy of 3.00mol of N2 gas at 25c?

18600j

Explanation:

It is given that,

Number of moles = 3

Temperature, T = 25°C = 25+273 = 298 K

The internal energy of N₂ gas is given by :

U=f\times nRTU=f×nRT

f is degrees of freedom. For diatomic gas, degree of freedom is equal to 5/2. So,

\begin{gathered}U=\dfrac{5}{2}\times 3\times 8.31\times 298U=18572.85\ J\end{gathered}

U=

2

5×3×8.31×298

U=18572.85 J

or

U = 18600 J

So, the internal energy of the gas is 18,600 J

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..