A block of mass M = 10 kg sits on an inclined plane with an adjustable angle q with respect to the horizontal. The coefficient of static friction between the box and the plane is µ! = 0.5. The end of the inclined plane is slowly lifted, increasing the angle q. At some point the block start to slide down the plane. Find the largest angle q (in degrees) at which the block stays at rest.

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j