An acrobat on skis starts from rest 50.0 m above the ground on a frictionless track and flies off the track
at a 45.0° angle above the horizontal and at a height
of 10.0 m. Disregard air resistance.
a. What is the skier's speed when leaving the
track?
b. What is the maximum height attained?

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

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